Răspuns:
Explicație pas cu pas:
rest < impartitor, deci rest<7
nr∈{7·125+0, 7·125+1, 7·125+2, 7·125+3, 7·125+4, 7·125+5, 7·125+6}
deci nr∈{875, 876, 877, 878, 879, 880, 881}
[tex]\it n+7=125\ rest\ r \Rightarrow \begin{cases}\it n=125\cdot7+r=875+r\ \ \ \ (1)\\ \\ \it r\in\{0,\ 1,\ 2,\ 3,\ 4,\ 5,\ 6\}\ \ \ \ (2)\end{cases}\\ \\ \\ (1),\ (2) \Rightarrow n\in\{875,\ 876,\ 877,\ 878,\ 879,\ 880,\ 881\}[/tex]
