Răspuns:
Explicație pas cu pas:
[tex]\sqrt{36} =6, \sqrt{5\frac{1}{4} } =\sqrt{\frac{10}{4}} =\frac{\sqrt{10} }{2} , \sqrt{7\frac{1}{9} } =\sqrt{\frac{64}{9}} =\frac{8}{3} , \sqrt{3\frac{1}{16} } =\sqrt{\frac{49}{16}} =\frac{7}{4},\sqrt{0,(4)} =\sqrt{\frac{4}{9}} =\frac{2}{3} ,\sqrt{4\frac{1}{4} } =\sqrt{\frac{17}{4}} =\frac{\sqrt{17} }{2} ,\sqrt{3^{2}2^{6} } =3x2^{3}=24[/tex]
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A ∩ N = {6, 24}
A ∩ Q = {8/3, 7/4, 2/3}
A ∩ (R \ Q) = celelalte numere
