[tex]\it \sqrt{0.(3)}=\sqrt{\dfrac{3}{9}}=\dfrac{\sqrt3}{3}\\ \\ \\ \sqrt{0.(2)}=\sqrt{\dfrac{2}{9}}=\dfrac{\sqrt2}{3}[/tex]
Expresia devine:
[tex]\it \Big(\dfrac{\sqrt3}{3}-\dfrac{2\sqrt3}{3}\Big)\cdot\sqrt3-\Big(\dfrac{\sqrt2}{3}-\dfrac{4}{3\sqrt2}\Big)\cdot\sqrt2 =\Big(-\dfrac{\sqrt3}{3}\Big)\cdot\sqrt3-\Big(\dfrac{2}{3}-\dfrac{4}{3}\Big) =\\ \\ \\ =-\dfrac{3}{3}-(-\dfrac{2}{3})=-1+\dfrac{2}{3}=-\dfrac{1}{3}[/tex]
