Răspuns:
4radical din 6
22radical din 2
6radical din 14 supra 7
3 radical din 14 supra 35
5 radical din 3 + 5 radical din 2
(la ultima asa rămâne)
Răspuns:
Vezi rezvolvarile mai jos:
Explicație pas cu pas:
[tex]4\sqrt{6} +\sqrt{24} - \sqrt{50} +\sqrt{54} =\\4\sqrt{6} + 2\sqrt{6} - 5\sqrt{2} + 3\sqrt{6} =\\6\sqrt{6} - 5\sqrt{2} + 3\sqrt{6} =\\9\sqrt{6} -5\sqrt{2} \\\\[/tex][tex]8\sqrt{20} : 4\sqrt{10} -15\sqrt{6} : (-3\sqrt{3}) + 6\sqrt{14} : (-2\sqrt{7} )=\\2\sqrt{2} + 5\sqrt{2} - 3\sqrt{2} =\\7\sqrt{2} - 3\sqrt{2} =\\\\5\sqrt{2}[/tex][tex]\frac{12}{\sqrt{14} } \\\\Rationalizam fractia cu \sqrt{14} \\\\\\\frac{12}{\sqrt{14} } = \frac{12\sqrt{14} }{\sqrt{14} * \sqrt{14} } = \frac{12\sqrt{14} }{14} \\\\\\Simplificam fractia prin 2:\\\\\\ \frac{12\sqrt{14} }{14} = \frac{6\sqrt{14} }{7}[/tex][tex]\frac{3\sqrt{2} }{5\sqrt{7} } \\Rationalizam fractia cu \sqrt{7} \\\\\frac{3\sqrt{2} }{5\sqrt{7} } = \frac{3\sqrt{2} * \sqrt{7} }{5\sqrt{7} *\sqrt{7} } = \frac{3\sqrt{14} }{5 * 7} = \frac{3\sqrt{14} }{35}[/tex][tex]\frac{5}{\sqrt{3} - \sqrt{2} } =\\\\Rationalizam fractia cu \sqrt{3} + \sqrt{2}\\\\ \frac{5}{\sqrt{3} - \sqrt{2} } = \frac{5 * (\sqrt{3} +\sqrt{2})}{(\sqrt{3}-\sqrt{2} )( \sqrt{3} +\sqrt{2} )} = \frac{5 * (\sqrt{3} +\sqrt{2})}{ 3 - 2} = \frac{5 * (\sqrt{3} +\sqrt{2})}{1} = 5 * (\sqrt{3} +\sqrt{2})[/tex]
