a/b = 2/3
Scriem proportia derivata:
a/2 = b/3 = k, de unde:
a = 2k si b = 3k
Trebuie sa calculam (3a + 2b)/(2a + 3b). Inlocuim in aceasta relatie a si b scrise in functie de k:
(3a+2b)/(2a+3b) = (3*2k+2*3k)/(2*2k+3*3k) = (6k+6k)/(4k+9k) = 12k/13k = 12/13
R: 12/13
a/b = 2/3
a/2 = b/3 = k
a = 2k
b = 3k
(3a+2b)/(2a+3b) =
= (6k+6k)/(4k+9k)
= (12k)/(13k)
= 12/13
