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Cati moli de Fe se gasesc in 232g Fe3 O4.​

Răspuns :

Miu = 3×56+4×16 = 232 g/mol

232 g Fe3O4 .................... 3x56 g Fe

232 g ................................. m

= 168 g Fe

A.Fe = 56

=> nr.moli = 168/56 =3 moli Fe