1)
100-47-46,4 = 6,6% H
C = 47/12 = 3,92
H = 6,6/1 = 6,6
Cl = 46,4/35,5 = 1,31
impartim rezultatele la cel mai mic multiplu comun... 1,31
=> C = 3, H = 5 si Cl = 1
b)
CH2=CH-CH2Cl = clorura de alil
CH2=C(Cl)-CH3 = 2-cloropropena
ClCH=CH-CH3 = 1-cloropropena (Z-E)
c)
reactie de substitutie in pozitia alilica
CH2=CH-CH3 + Cl2 --500oC--> CH2=CH-CH2Cl + HCl
reactie de aditie
CH≡C-CH3 + HCl --HgCl2/170oC--> CH2=C(Cl)-CH3
2)
1-bromobutan ----> 2-bromobutan
C-C-C-C(Br) + H2O --NaOH/EtOH--> C-C-C=C
C-C-C=C + HBr --> C-C-C(Br)-C
C6H6 -----> C6H5-CHO
C6H6 + CH3Cl --AlCl3--> C6H5-CH3 + HCl
C6H5-CH3 + 2Cl2 --lumina--> C6H5-CHCl2 + 2HCl
C6H5-CHCl2 + H2O --NaOH--> C6H5-CHO + 2HCl
3)
alchena = CnH2n, miu = 42 g/mol
=> 14n = 42 => n = 3
=> A = C3H6
PV = nRT => n = PV/RT
= 12,3x3/0,082x(273+27)
= 1,5 moli propena
a)
C3H6 + HCl --> C3H7Cl
C3H7Cl + H2O --NaOH--> C3H7OH + HCl
b)
1,5 moli a moli
C3H6 + HCl --> C3H7Cl
1 1
a moli m g
C3H7Cl + H2O --NaOH--> C3H7OH + HCl
1 60
=> m = 1,5x60/1 = 90 g C3H7OH la 100%.... dar la 75%...??
100% ........................ 90g
75% ............................ b = 67,5 g
