Fie CE inaltime
Rezulta tr CEB dr is
AE= CD = 12
Rezulta EB = 12cm
Rezulta in tr CEB dr is
EB = EC= 12
BC =RAD 144+144= RAD 288= 12RAD2
a) Aria( B+b) ×h ÷2= (24+12) ×12 ÷2= 36×6=216cm patrati
b) triunghiu ABC verificam din reciproca teoremei lui Pitagora
ACla a2a+ BC la a2a= AB la a2a
(12rad 2)² +(12rad2)² = 24²
288+288= 576
576=576 ,,A"
Rezulta tr ABC dr is
Rezulta AC_|_BC
c)