Răspuns:
Calculam A :
[tex]a = 2 {}^{35} - 2 {}^{34} - 2 {}^{33} [/tex]
[tex]a = (2 {}^{2} - 2 - 1) \times 2 {}^{33} [/tex]
[tex]a = (4 - 2 - 1) \times 2 {}^{33} [/tex]
[tex]a = 1 \times 2 {}^{33} [/tex]
[tex]a = 2 {}^{33} [/tex]
Calculam B :
[tex]b = 3 {}^{24} - 3 \times 3 {}^{23} + 3 {}^{22} [/tex]
[tex]b = 3 {}^{24} - 3 {}^{24} + 3 {}^{22} [/tex]
[tex]b = 3 {}^{22} [/tex]
Le comparam :
[tex]2 {}^{33} < 3 {}^{22} [/tex]
SPER CA TE AM AJUTAT!
Răspuns:
2^33(4-2-1)=2^33 ; 3^24-3^24+3^22=3^22 ;
Explicație pas cu pas:
(2^3)^11<(3^2)^11; 8^11<3^11 ; a<b
