Răspuns:
[tex] \frac{3 \sqrt{3} }{2 \sqrt{3} + 3 } = (radicalizam \: cu \: radical \: din \: trei) \: \: \: \frac{3 \times 3}{2 \times 3 + 3} = \frac{9}{6 + 3} = \frac{9}{9} = 1[/tex]
[tex] \frac{12}{3 \sqrt{2} - 4 } = \frac{12 \sqrt{2} }{3 \times 2 - 4} = \frac{12 \sqrt{2} }{2} = 6 \sqrt{2} [/tex]
succes!
