Răspuns:
[tex]\sqrt{13-4\sqrt{3} }* [(\sqrt{3}+2)^{2}+\frac{2}{\sqrt{3}+2} -(4-\sqrt{6})(4+\sqrt{6})]=\\\sqrt{(2\sqrt{3}-1 )^{2}} *[3+4+4\sqrt{3} +\frac{2*(2-\sqrt{3}) }{(2+\sqrt{3})(2-\sqrt{3})} -(4^{2}-(\sqrt{6})^{2})]=(2\sqrt{3}-1)*[7+4\sqrt{3} +4-2\sqrt{3}-16+6]=(2\sqrt{3}-1)*(2\sqrt{3}+1)=(2\sqrt{3})^{2}-1^{2}=12-1=11[/tex]
Explicație pas cu pas:
