a)
A = propena , CH2=CH-CH3
B = metan, CH4
C = acid acetic, CH3COOH
D = diclorometan, CH2Cl2
c)
165g A impur .................... 100%
m.pur ................................ 80%
= 132 g A
132g n moli
C3H6 + H2 --> C3H8
42 1
=> n = 132/42 = 3,14 moli H2 in conditii normale..... dar in conditiile din problema ....??
PV = nRT
=> V = nRT/P
= 3,14x0,082x(273+27)/0,5
= 154,63 L H2
d)
112 cm3 A = 0,123 L A
0,123 L/22,4 = 0,0055 moli A
0,0055 moli
CH2=CH-CH3 + 5[O] --> CO2 + H2O + CH3COOH /x3
3
n moli
K2Cr2O7 + 4H2SO4 --> K2SO4 + Cr2(SO4)3 + 4H2O + 3[O] /x5
5
=> n = 0,0055x5/3 = 0,00917 moli K2Cr2O7
stim ca Cm = niu/Vs => Vs = niu/Cm
= 0,00917/0,5 = 0,0183 L sol K2Cr2O7
sau 18,33 mL sol K2Cr2O7
