Răspuns:
a[tex]a^{2} = 12[/tex]
Explicație pas cu pas:
a = ·[tex]a = \sqrt{5-2\sqrt{6} } + \sqrt{5+2\sqrt{6} } =\\ \sqrt{\sqrt{3} ^{2} -2\sqrt{3} \sqrt{2} + \sqrt{2} ^{2} } +\sqrt{\sqrt{3} ^{2} +2\sqrt{3} \sqrt{2} + \sqrt{2} ^{2} }=\\ \sqrt{(\sqrt{3} -\sqrt{2} )^{2} } + \sqrt{(\sqrt{3}+\sqrt{2} )^{2} } =\\ \sqrt{3} -\sqrt{2} +\sqrt{3} +\sqrt{2} =\\ 2\sqrt{3} \\a^{2} =(2\sqrt{3}) ^{2} =12[/tex]
