Răspuns:
[tex]\sqrt{4x+1}=2,~ridicam~la~patrat,~ (\sqrt{4x+1})^{2}=2^{2},~4x+1=4,~4x=4-1,~4x=3,~x=\frac{3}{4} \\ \sqrt{6x-2}=10,~ridicam~la~patrat,~ (\sqrt{6x-2})^{2}=10^{2},~6x-2=100,~6x=100+2,~6x=102,~x=\frac{102}{6} =17\\\\\sqrt{5x-3}=7,~ridicam~la~patrat,~ (\sqrt{5x-3})^{2}=7^{2},~5x-3=49,~5x=49+3,~5x=52,~x=\frac{52}{5} =10\frac{2}{5} \\[/tex]
Explicație pas cu pas:
