Răspuns:
[tex]b=(\frac{3}{\sqrt{3}}+\frac{6}{\sqrt{4*3} }-\frac{60}{\sqrt{16*3} })*\frac{30}{2*\sqrt{25*3} }=(\frac{3}{\sqrt{3} }+\frac{6}{2*\sqrt{3}} -\frac{60}{4*\sqrt{3} })*\frac{30}{2*5*\sqrt{3} } =\\=(\frac{3}{\sqrt{3} }+\frac{3}{\sqrt{3} }-\frac{15}{\sqrt{3} })*\frac{3}{\sqrt{3} }=-\frac{9}{\sqrt{3} }*\frac{3}{\sqrt{3} }=-9[/tex]
Explicație pas cu pas:
