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calculati respectand ordinea operatiilor (3^0×3×3^13÷3^5+1):((3^2)3×27+3^0)​

Răspuns :

(3^0 * 3 * 3^13 : 3^5 + 1) : [(3^2)^3 * 27 + 3^0] =

= (1 * 3^14 : 3^5 + 1) : (3^6 * 3^3 + 1) =

= (3^9 + 1) : (3^9 + 1) =

= 1

Răspuns:

(0×3×3^13minus5 +1):(3^2×3×27+0)

(0×3×3^8+1):(9×3×27+0)

(0×3×6.561+1):(27×27+0)

(0×6561+1):(729+0)

(0+1):729

1:729

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