Răspuns:
[tex]\sqrt[3]{2}-\sqrt[3]{16} +\sqrt[3]{54}-\sqrt[3]{128} = \sqrt[3]{2}-\sqrt[3]{2^{4}} +\sqrt[3]{3^{3}*2}-\sqrt[3]{2^{7}} = \sqrt[3]{2}-\sqrt[3]{2^{3}*2} +\sqrt[3]{3^{3}*2}-\sqrt[3]{(2^{2})^{3}*2} = \sqrt[3]{2}-2*\sqrt[3]{2} +3*\sqrt[3]{2}-4*\sqrt[3]{2} =\sqrt[3]{2}*(1-2+3-4)=-2*\sqrt[3]{2}[/tex]
Explicație pas cu pas:
Se aplica proprietatea
[tex]\sqrt[n]{a^{n}} =a[/tex]
