a)
prima = izomerizare
a doua = dehidrogenare
b)
288 kg m kg
C5H12 -----> C5H12
72 72
=> m = 288x72/72 = 288 kg i-pentan la rand de 100%.., dar la 50%... cat...??
100% .............. 288 kg
50% ................. n = 144 kg i-pentan
144 kg a kg
C5H12 -----> C5H8 + 2H2
72 68
=> a = 144x68/72 = 136 kg izopren la 100%
100% ............. 136 kg
80% ................ b = 108,8 kg izopren
