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Sa se determine primii doi termeni ai progresiei geometrice daca: b10=1024 ,q=2. b=64,q=4.

Răspuns :

bk = b1 * q^(k-1)

a) Atunci b10 = b1 * q^9 => 1024 = b1 * 2^9 => 1024 = b1 * 512 => b1 = 1024/512

b1 = 2

b2 = b1 * q = 2 * 2 = 4

b)  b6 = 64, q = 4

b6 = b1 * q^5

64 = b1 * 4^5

4^3 = b1 * 4^5

b1 = 4^3/4^5 = 1/4^2 = 1/16

b2 = b1 * q = 1/16 * 4 = 1/4