Răspuns:
mi=400g ; p=80% ; c=25% ; msHCl ; g,moli ,L H2
Explicație:
-se afla masa pura de Zn
p=mp.100: mi
mp=p.mi :100
mp=80 .400:100=320 g Zn
320g xg yg
Zn +2 HCl = ZnCl2 +H2
65g 2.36,5g 2g
x=320 . 73 : 65=359,38g HCl ( md )
ms= md.100 :c
ms=359,38 . 100 :25=1437,52 g sol. HCl
y=320 . 2 : 65=9,84 g hidrogen
n=9,84g : 2g/moli=4,92 moli H2
VH2=4,92moli .22,4 L/moli=110,208 L
2.
4moli xmoli
H2 +Cl2= 2HCl
1mol 2moli
x=4.2=8 moliHCl
m=8moli . 36,5g/moli=292g HCl
VHCl=8moli .22,4 L/moli=179,2 L
3.
xmoli 4moli
N2 + 3H2=2NH3
1mol 2moli
x=4:2=2moli N2
m=2moli.28g/moli=56 g azot
VN2=2moli .22,4 L/moli=44,8 L
MN2=2.14=28g/moli