Răspuns:
Explicație:
-se afla nmasa solutiei de NaOH
ro = ms : Vs
ms = ro . Vs
ms= 110g/l . 0,5 l=55 g sol. NaOH
-se afla md sol. de NaOH
md=c. ms :100
md=10. 55 : 100=5,5 g NaOH
5,5 g xg
3 NaOH + FeCl3= Fe(OH)3 +3NaCl
3. 40g 107g
x=5,5 . 107 : 3.40=4,9 gFe(OH)3
n=4,9g : 107g/moli=0,045 moli
MNaOH=23 +16 +1=40---->40g/molio
MFe(OH)3=56 +3 .16 +3=107 ---->107g/moli