Răspuns:
Explicație pas cu pas:
2^2^0 = 2^1
( 2⁶)⁵x { 3⁴ x 28 - [ 3 - ( 2³ x 5³ - 3²x 10²- 5²): 5² ] : 10⁴- 2¹x 3⁴} =
= 2³⁰ x { 81 x 28 - [3 - (8x5 - 3²x 2²- 1 ) x 5² : 5²] : 10⁴ - 2 x 81} =
= 2³⁰ x { 81x 28 - [ 3 - ( 40 - 9x4 - 1) x 1 ] : 10⁴ - 2 x 81} =
= 2³⁰ x [ 81 x 28 - ( 3 - 3) : 10⁴ - 2 x 81] =
= 2³⁰ x ( 81 x 28 - 0 : 10⁴ - 2 x 81 ) =
= 2³⁰x 81 x ( 28 - 2) =
= 2³⁰ x 3⁴ x 26 =
= 2³⁰ x 3⁴ x 2 x 13
= 2³¹ x 3⁴ x 13
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SAU:
= 2⁶ˣ⁵ x { 81 x 28 - [ 3 - (10³ - 30² - 25 ) : 25 ] : 10⁴ - 2 x 81 } =
= 2³⁰ x { 2268 - [ 3 - ( 1000 - 900 - 25 ) : 25 ] : 10⁴- 162} =
= 2³⁰ x [ 2268 - ( 3 - 75 : 25 ) : 10⁴ - 162 ] =
= 2³⁰ x ( 2268 - 0 : 10⁴ - 162 ) =
= 2³⁰ x ( 2268 - 0 - 162 ) =
= 2³⁰ x 2106 =
= 2³⁰ x 2 x 3⁴ x 13
= 2³¹ x 3⁴ x 13
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2⁷ x 4⁵ x 3²⁵ =
= 2⁷ x( 2²)⁵ x 3²⁵=
= 2⁽⁷⁺²ˣ⁵⁾ x 3²⁵ =
= 2¹⁷ x 3²⁵
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2³¹ x 3⁴ x 13 > 2¹⁷ x 3²⁵ fals
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2³¹ x 3⁴ x 13 cu 2¹⁷ x 3²⁵ l : 2¹⁷ x 3⁴
2³¹⁻¹⁷ = 2¹⁴
2¹⁴ x 13 cu 3²¹ ( 3¹⁴ x 3⁷)
2¹⁴ x 13 < 3¹⁴ x 3⁷; 2 < 3, dar si 13 < 3⁷
