Răspuns:
Explicație:
2.
270 g Al
g Al2O3
270g xg
4 Al + 3O2 =2 Al2O3
4 .27g 2.102g
x=270 . 204 :108=510g Al2O3
3.
ms HCl= 800g
c=36,5%
moli CaCl2
g Ca
- se afla md sol. de HCl
md= c.ms :100
md=36,5 .800 : 100=292 g HCl
yg 292g xg
Ca +2 HCl = CaCl2 + H2
40g 2.36,5g 111 g
x=292.111 : 73=444 g CaCl2
n=444 g : 111 g/moli=4 moli CaCl2
y=292.40 : 73=160 g Ca
MAl2O3=2.27 +3.16=102 ---->102g/moli
MHCl=1 +35,5=36,5 ----->36,5 g/moli
MCaCl2=40 + 3.35,5=111 ---->111 g/moli