Răspuns:
-calculez moli acid,bazadin solutiile date
c=mdx100/ms= mdx100/roxv----> md= 5,4x1,025x396/100g=21,92gHCl
niu=m/M= 21,92/36,5mol=0,6molHCl
c= niu/V= niu/m/ro---> niu=1,6x806/1,074x1000=1,2molKOH
DEOARECE in reactia dintre HCl si KOH, intra 1 mol acid, 1 mol baza si rezulta 1mol apa, in acest caz rezulta 0,6molH2O(baza este in exces)
stiu: ΔHneutr= -13,7kcal/molH2O
1mol H2O..........13,7KCAL
0,6MOL..............X= 8,2kcal------se degaja
Q= (m,acid+m,baza)xcxΔt---> Δt= 8200x4,184j/ 1212x4,184 grd=6,7grade
Explicație:
