Răspuns:
[tex]3-6x[\frac{2}{3} + (\frac{1}{3}+\frac{5}{7} ) / (\frac{-22}{7}) ] =[/tex]
[tex]3-6x[\frac{2}{3} +(\frac{7}{21} + \frac{15}{21} )/ (\frac{-22}{7} )] =\\3-6x[\frac{2}{3} + \frac{22}{21} / (\frac{-22}{7})]=\\ 3-6x{\frac{2}{3} + \frac{22}{21} x (\frac{7}{-22} )]=\\[/tex]
[tex]3-6x[\frac{2}{3} + (-\frac{1}{3} )=\\ =3-6x(\frac{2}{3}-\frac{1}{3}) = \\ = 3-6x\frac{1}{3}=\\ =3-2=\\=1[/tex]
