Răspuns:
-din 64 000kg Fe2O3se foloseste 80%
64000 . 80 :100=59200 kg Fe2O3
Explicație:
xkg 59200kg
4 FeS2 +11 O2= 2Fe2O3 +8 SO2
4.120kg 2.160kg
x=480 . 59200 : 320=88800 kg FeS2
MFeS2=56 +2.32=120--->120kg/kmoli
MFe2O3=2.56 +3.16=160----->160kg/kmoli