Răspuns:
13.
b.) (3^20)^4*(9^10)^2*27^40=
3^80*9^20*27^40=
3^80*(3^2)^20*(3^3)^40=
3^80*3^40*3^120=
3^(80+40+120)
3^240
c.) 25^10*5^14:125^10=
(5^2)^10*5^14:(5^3)^10=
5^20*5^14:5^30=
5^34:5^30=
5^4
d.) 2^5*4^2*32^3=
2^5*(2^2)^2*(2^5)^3=
2^5*2^4*2^15=
2^(5+4+15)=
2^24
Explicație pas cu pas: