Răspuns:
Explicație pas cu pas:
[tex]\frac{4-3\sqrt{6} }{2\sqrt{3} } -\frac{5\sqrt{6} -7}{4\sqrt{2} } +\frac{3+2\sqrt{6} }{5\sqrt{3} } -\frac{4\sqrt{6} -3}{6\sqrt{2} } =\\ \frac{(4-3\sqrt{6})\sqrt{3} }{6} -\frac{(5\sqrt{6}-7)\sqrt{2} }{8} +\frac{(3+2\sqrt{6} )\sqrt{3} }{15} -\frac{(4\sqrt{6}-3)\sqrt{2} }{12} =[/tex][tex]\\ \frac{(4-3\sqrt{6})20\sqrt{3} }{120} -\frac{(5\sqrt{6}-7)15\sqrt{2} }{120} +\frac{(3+2\sqrt{6} )8\sqrt{3} }{120} -\frac{(4\sqrt{6}-3)10\sqrt{2} }{120} =\\ \frac{80\sqrt{3}-60\sqrt{18} -75\sqrt{12} +105\sqrt{2} +24\sqrt{3} +16\sqrt{18} -40\sqrt{12} +30\sqrt{2} }{120} =\\ \frac{80\sqrt{3} -180\sqrt{2}-150\sqrt{3} +105\sqrt{2} +24\sqrt{3}+48\sqrt{2} -80\sqrt{3} +30\sqrt{2} }{120} =\\ \frac{3\sqrt{2}-126\sqrt{3} }{120} =\\ \frac{\sqrt{2}-42\sqrt{3} }{40}[/tex]
