n:10 = c rest r
c=r
c,r=0 => n=10×0+0 => n=0
c,r=1 => n=10×1+1 => n=11
c,r=2 => n=10×2+2 => n=22
c,r=3 => n=10×3+3 => n=33
c,r=4 => n=10×4+4 => n=44
c,r=5 => n=10×5+5 => n=55
c,r=6 => n=10×6+6 => n=66
c,r=7 => n=10×7+7 => n=77
c,r=8 => n=10×8+8 => n=88
c,r=9 => n=10×9+9 => n=99
Atât, deoarece restul (r) trebuie să fie mai mic decat impartitorul!
r<î (rest<impartitor)
