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Determinati nummerele naturale a, b, c stiind ca:
a+b=100, b+c=110, a+c=90


Răspuns :

2*a+2*b+2*c=100+110+90=300

300:2=150

A+b+c=150

B=150-90=60

C=150-100=50

A=150-110=40

Succes:)

a + b = 100

b + c = 110

a + c = 90

a + b + b + c = 100 + 110

a + 2 × b + c = 210

90 + 2 × b = 210

2 × b = 210 - 90

2 × b = 120

b = 120 : 2

b = 60

a = 100 - b

a = 100 - 60

a = 40

c = 90 - a

c = 90 - 40

c = 50