d) [tex]\it \sqrt{\frac{8}{9} } - \sqrt{2} + \frac{1}{6} \cdot \sqrt{2} = \frac{\sqrt{8} }{\sqrt{9} } - \sqrt{2} ~+ ~\frac{\sqrt{2} }{6} = ~^{2)} \frac{2\sqrt{2} }{3} - ~^{6)} \sqrt{2} ~+ ~\frac{\sqrt{2} }{6} = 4\sqrt{2} ~- ~6\sqrt{2} ~+ ~\sqrt{2} = -\sqrt{2}[/tex]
