Răspuns:
Explicație pas cu pas:
ex4
Din faptul ca radacina patrata nu e negatica, ⇒ -x>0, atunci si (-x)²⁰¹³>0
ex5
[tex]|\frac{1}{3}-\frac{1}{2} |+|\frac{1}{4}-\frac{1}{3} |+|\frac{1}{5}-\frac{1}{4} |+|\frac{1}{6}-\frac{1}{5} |=|\frac{1}{2}-\frac{1}{3} |+|\frac{1}{3}-\frac{1}{4} |+|\frac{1}{4}-\frac{1}{5} |+|\frac{1}{5}-\frac{1}{6} |=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4} +\frac{1}{4}-\frac{1}{5} +\frac{1}{5}-\frac{1}{6} =\frac{1}{2} -\frac{1}{6}=\frac{3}{6}-\frac{1}{6}=\frac{2}{6} =\frac{1}{3}\\\frac{1}{3}=\frac{1}{3}[/tex]
