Răspuns:
M,PCl3=(31gP+ 3x35,5gCl)/mol= (31+106,5)g/mol= 137,5g/mol
c 137,5g clorura................106,5gCl
200g..................................x=m=200x106,5/137,5 =.........calculeaza
d 1molPCl3 contine 3molCl
137,5g.......................3molCl
200g.....................x=4,36 molCl
1mol atomi Cl.............N,A= 6,023X10²³atomi(numarul lui Avogadro)
4,36mol......................x=26,3x10²³atomi Cl
Explicație: