Răspuns:
Explicație:
A.
1. pozitiva
2. 6,023.10²³ atomi
3. omogen
4. trei
5. Li2O
B.
1. O
2. a
3. b
4. c
5. p=80 ( 100- 20 =80 )
2t=2000kg
p=mp.100 : mt
mp=p.mt :100
mp=2000 .80 :100=1600 kg sare pura
II .
1. MH2SO4=2+32+4.16=98-----> 98g/moli
MFe(OH)3=56 +3.16 + 3=
MCuSO4=64 +32 +4.16=
2.
CuCO3=CuO + CO2 reactie de descomp.
Cu O + 2HCl = CuCl2 + H2O r. de schimb
CO2 +2 NaOH = Na2CO3 + H2O r .de schimb
3. 2Mg + O2=2MgO
4.
Al(OH)3
r.a.=1 : 3 : 3
r.m.= AAl : 3AO : 3AH= 27 : 3.16 : 3
= 27 : 48 : 3
=9 : 16 : 1
comp. proc. prin r.m.
9+16 + 1=26
26g Al(OH)3--------9g Al------16g O ---------1g H
100 g--------------------------x----------y-----------------z
x=100.9: 26=
y=100.16: 26
z=100.1: 26=
5.
MHNO3=1+14 +3.16=63------>63g/moli ; [sunt 5atomi in total]
1mol HNO3---------- 5 . 6,023.10²³atomi HNO3
3moliHNO3--------------x
x=3. 5 .6,023.10²³ atomi HNO3
