Răspuns:
formula chimica presupusa KClOx
M=[(39gK+35,5gCl)+16X,gO]/mol=(74,5+16X)g/mol
M,KCl=74,5g/mol
in (74,5+ 16x)g sare..........74,5gKCl
1,02............................................0,62
1,02x74,5= 0,62(74,5+16x)----> x=3-----> KClO3-clorat de potasiu
Explicație: