9+10+11+....+30=?
Teorema sumei lui Gauss (cand termenii sunt naturali ,crescand cu cate 1):
a+(a+1)+(a+2)+...+(a+n)=[(a+n) x (a+n+1)]/2
9+10+11+....+30= (1+2+3+...+7+8+9+...+29+30)- (1+2+...+8)
= (30 x 31)/2 - (8 x 9)/2
=31 x 15 - 4 x 9
=465-36
=429