[tex]Daca\ a,b,c\ d.p.\ cu\ 2,3,5\, atunci\ are\ loc\ relatia\\\frac{a}{2}=\frac{b}{3}=\frac{c}{5}=k\\\\\frac{a}{2}=k\ =>\ a=2k\\\frac{b}{3}=k\ =>\ b=3k\\\frac{c}{5}=k\ =>\ c=5k\\\\4a-2b+3c= 4*2k-2*3k+3*5k\\51=8k-6k+15k\\51=17k\\k=3\\a=2*k=2*3=6\\b=3*k=3*3=9\\c=5*k=5*3=15[/tex]
