[tex]\displaystyle\bf\\\left(\frac{1}{8}+\frac{1}{8}\times4\right)\times\left(\frac{1}{2}-\frac{2}{4}\right)=\\\\\\=\left(\frac{1}{8}+\frac{1}{8}\times4\right)\times\left(\frac{1}{2}-\frac{1}{2}\right)=\\\\\\=\left(\frac{1}{8}+\frac{1}{8}\times4\right)\times0=\boxed{\bf0}[/tex]