Răspuns:
C,m3= (niu1+niu2)/(Vs1+Vs2+Vapa)
solutia1
Vs1= 200ml------>ms1=roxVs1= 200mlx1,84g/ml= 368g 1ml=1cm³
c1=md1x100/ms1---> md1= 98x368/100g=360.6gH2SO4
niu,1= md1/M= 360,6/98mol=3,68mol H2SO4
solutia2
c,m= niu2/Vs2-->niu2= 1mol/lx0,250l= 0,25mol
apa
m,apa= 150g---> V,apa= 150g/1gml= 150ml=0,15l
c,m3= ((3,68+0,25)mol/(0,2+0,25+0,15)l=3,93mol/0,6l=6,55mol/l
in aceasta solutie, in 0,6l sunt 3,93mol H2SO4
1mol.............2mol
H2SO4+2NaOH---> Na2SO4 + 2H2O
3,93mol........x= 7,86 molNaOH
C.m= niu/V---> V=7,86mol/2mol/l= 3,93 l solutie NaOH
Explicație:
