Răspuns:
a, b € [1, 9]
a != 0
a) 17/a^2+b^2 = 1
a^2 + b^2 = 17
a = 1, b = 4
a = 4, b = 1
ab € {14, 41}
b) 3/a+b > 1
3 > a+b
a+b < 3
a = 1, b = 1
a = 2, b = 0
ab € {11, 20}
c) a+b/4 < 1
a+b < 4
a = 1, b = 2
a = 2, b = 1
a = 3, b = 0
ab € {12, 21, 30}
Sper ca ai inteles :D
Răspuns:
Explicație pas cu pas:
a) (a,b)∈{(1,4), (4,1)}, deoarece a²+b²=17
b) (a,b)∈{(0,1), (0,2), (1,1), (2,0)}, deoarece 3>a+b
c) (a,b)∈{(0,0), (0,1), (0,2), (0,3), (1,0),(1,1),(1,2),(2,0),(2,1),(3,0)}, deoarece a+b<4
