(a,b)=15 si [a,b]=450
a=15x si b=15y; (x;y)=1
a•b=15•450=6750
15x•15y=6750 /:225
=>x•y=30
(x;y)={(1; 30); (2; 15); (3; 10); (5; 6); (6; 5); (10; 3); (15; 2); (30; 1)}
(a;b)={(15;450); (30;225); (45;150); (75;90); (90;75); (150;45); (225; 30); (450; 15)}