Răspuns:
12
Explicație pas cu pas:
[tex]\frac{(6+12+18+24+...+600)^{2} }{3+6+9+12+...+300}:(1+2+3+...+100)=\frac{(6(1+2+3+...+100))^{2}}{3(1+2+3+...+100)}*\frac{1}{1+2+3+...+100} =\frac{6^{2} (1+2+3+...+100)^{2}}{3(1+2+3+...+100)^{2}}=\frac{36}{3} =12[/tex]