Explicație pas cu pas:
[tex] a = ( \frac{ \sqrt{2} }{ \sqrt{3} } - \sqrt{5} )^{2} - \sqrt{180} (1 - [/tex]
[tex] - 1 + \sqrt{2} - \frac{ \sqrt{18} }{6} + \sqrt{3} - \frac{ \sqrt{48} }{12}) = [/tex]
[tex] = ( \frac{2}{3} - \frac{2 \sqrt{10} }{ \sqrt{3} } + 5) - 6 \sqrt{5} ( \sqrt{2} - [/tex]
[tex] - \frac{3 \sqrt{2} }{6} + \sqrt{3} - \frac{4 \sqrt{3} }{12}) = ( \frac{2}{3} - \frac{2 \sqrt{30} }{3} + [/tex]
[tex] + \frac{5}{3} ) - 6 \sqrt{5} ( \frac{12 \sqrt{2} }{12} - \frac{6 \sqrt{2} }{12} + \frac{12 \sqrt{3} }{12} ) - [/tex]
[tex] - \frac{4 \sqrt{3} }{12} ) = ( \frac{7}{3} - \frac{2 \sqrt{3} }{3} ) - 6 \sqrt{5} ( \frac{6 \sqrt{2} }{12} + [/tex]
[tex] + \frac{12 \sqrt{3} }{12} - \frac{4 \sqrt{3} }{12} ) = ( \frac{7}{3} - \frac{2 \sqrt{3} }{3} ) - [/tex]
[tex] - (\frac{36 \sqrt{10} }{12} + \frac{72 \sqrt{15} }{12} - \frac{24 \sqrt{15} }{12} ) = [/tex]
[tex] = \frac{7}{3} - \frac{2 \sqrt{3} }{3} - \frac{36 \sqrt{10} }{12} - \frac{72 \sqrt{15} }{12} + [/tex]
[tex] + \frac{24 \sqrt{15} }{12} = \frac{7}{3} - \frac{2 \sqrt{3} }{3} - \frac{9 \sqrt{10} }{3} - [/tex]
[tex] - \frac{18 \sqrt{15} }{3} + \frac{6 \sqrt{15} }{3} = \frac{7}{3} - \frac{2 \sqrt{3} }{3} - [/tex]
[tex] \frac{9 \sqrt{10} }{3} - \frac{12 \sqrt{15} }{3} [/tex]
Cred că exercițiul nu este corect.
