Răspuns:
Explicație pas cu pas:
a·5=b·3=k
a·5=k. a=k/5
b·3=k, b=k/3
[tex]\frac{3a+b}{2b-a} =(3*\frac{k}{5} +\frac{k}{3} ):(2*\frac{k}{3}-\frac{k}{5})=(\frac{3*3k}{5*3}+\frac{5k}{3*5}):(\frac{2k*5}{3*5}-\frac{3k}{5*3})=\frac{9k+5k}{15}:\frac{10k-3k}{15} =\frac{14k}{15}:\frac{7k}{15} =\frac{14k}{15}*\frac{15}{7k} =\frac{14k}{7k} =2[/tex]
