[tex]\ln x \rightarrow \text{functie strict crescatoare pe }(0,+\infty)\\ \\ \ln 2= \log_{e}2 <1,\quad (e\approx 2.71, \text{baza e mai mare decat argumentul.})\\\\\pi \approx 3.14 \\ \\ \ln 3 = \log_{e}3 > 1\\\\ e^x\to \text{ functie strict crescatoare pe }\mathbb{R}\\\\2<\pi \Rightarrow e^2 <e^\pi \Rightarrow 3<e^2<e^\pi \Rightarrow \ln 3<\ln e^2<\ln e^\pi \Rightarrow \\ \\ \Rightarrow \ln 3<2<\pi \Rightarrow \ln 3 <\pi \\ \\ \\ \text{Ordinea este: }\quad \boxed{\ln 2,\,1,\,\,\ln 3,\,\pi}[/tex]
