Termodinamica - caldura necesara unui proces

ν=1 kmol=10³ moli
R=8310 J/(K*kmol)=8,31 J/(K*mol)
T₁=27°C=300 K
V= constant
p₂=np₁=5p₁
p₁/T₁=p₂/T₂=>T₂=T₁p₂/p₁=5p₁*300/p₁=1500 K
Q=νCvΔT=νCv(T₂-T₁)=10³*5*8,31(1500-300)/2=8310*5*1200/2=49860000/2=24930000 J=24,93*10⁶ J