Răspuns:
x=2
y=-2
Explicație pas cu pas:
(4-2x)√3 + (y+2)·√2 = 0
(y+2)√2=(2x-4)√3
(y+2)/(2x-4)=√2/√3=√6/3 ∈R\Q (1)
dar se cer x, y∈Q⇒(y+2)/(2x-4)∈Q (2)
(1) si (2) CONTRADICTIE
atunci singura modalitate prin care
(4-2x)√3 + (y+2)·√2 = 0
este ca (4-2x)√3 = (y+2)·√2 = 0
adica 4-2x=0...x=2∈N⊂Q
y+2=0....y=-2∈Z⊂Q
as tricky as that!!!
urâ....ăăăăăstaa, intersanta problema!!
eu zic macar in vacanta, uita-o!! e cam de liceu
