ajutati-ma va rog!!
e urgent!
dau coroana!
multumesc

4^x+4^x*4+4^x*4^2==336
4^x e factor comun
4^x*(1+1*4+1*4^2)=336
4^x*(1+4+16)=336
4^x*21=336
4^x=336/21
4^x=16
4^x=4^2
4=4=>x=2∈N