∠A, ∠B d.p. 3,6
∠A+∠B=90° (complementare)
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∠A=? ∠B=?
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∠A/3=∠B/6= k°
∠A/3=k° => ∠A=3k°
∠B/6=k °=> ∠B=6k°
3k°+6k°=90°
9k°=90° / :9°
k°=10°
=> ∠A=3*10°=30°
∠B=6*10°=60°
=>CEL MAI MARE DINTRE UNGHIURI MĂSOARĂ 60°.
BAFTA!