In ΔABC , m(∡A)=90°=>tgC=AB/AC=>AC=AB/tgC=2√3/tg30°=2√3/√3/3=2*3√3/√3=6 cm=>AC=6 cm
In ΔABC , m(∡A)=90°=>sinC=AB/BC=>BC=AB/sin30°=2√3/1/2=2*2√3/1=4√3 cm=>BC=4√3 cm
fie AO⊥BC=>AO->inaltime
In ΔABC , m(∡A)=90°=>(teorema catetei):BA²=BO*BC<=>(2√3)²=BO*4√3<=>12=4√3BO |:4=>BO=3/√3=3√3/3=√3 cm=>BO=√3 cm
In ΔABC , m(∡A)=90°=>(teorema catetei):AC²=CO*BC<=>6²=CO*4√3<=>36=4√3CO |:4<=>9=√3CO=>CO=9/√3=9√3/3=3√3 cm
In ΔABC , m(∡A)=90°=>(teorema inaltimii):AO²=BO*OC=√3*3√3=3*3=9=>AO=√9=3 cm=>AO=3 cm
